Sk8-tEr
New Member
- Reaction score
- 5
If any1 is really good at math/physics...
I wanted to set variables for stuff, so to isolate these variables of the
projectile motion formulas in physics.
For the V formula
Vf = Vi + (a)(t)
Vi = Vf - (a)(t)
t = (Vf/a) - (Vi/a)
a = (Vf/t) - (Vi/t)
For the X formula
Xf = Xi + (Vi)(t) + (1/2)(a)(t squared)
Xi = Xf - (Vi)(t) - (1/2)(a)(t squared)
Vi = (Xf/t) - (Xi/t) - (1/2)(a)(t)
a = ((2)(Xf))/(t squared)
But for the last one.... to isolate t i'm not sure
I know the quadratic formula is (a)(x squared) + (b)(x) + (c) = 0
But I was wondering if it could be (a)(x squared) + (b)(x) + (c) = (d)
so...
Xf = (t = (-Vi +or- (the sqaure root of((Vi squared) -(4)(a/2)(Xi))))/2)
Does this work? where does Xf go actually and where does t go.... Can any1 help?
I wanted to set variables for stuff, so to isolate these variables of the
projectile motion formulas in physics.
For the V formula
Vf = Vi + (a)(t)
Vi = Vf - (a)(t)
t = (Vf/a) - (Vi/a)
a = (Vf/t) - (Vi/t)
For the X formula
Xf = Xi + (Vi)(t) + (1/2)(a)(t squared)
Xi = Xf - (Vi)(t) - (1/2)(a)(t squared)
Vi = (Xf/t) - (Xi/t) - (1/2)(a)(t)
a = ((2)(Xf))/(t squared)
But for the last one.... to isolate t i'm not sure
I know the quadratic formula is (a)(x squared) + (b)(x) + (c) = 0
But I was wondering if it could be (a)(x squared) + (b)(x) + (c) = (d)
so...
Xf = (t = (-Vi +or- (the sqaure root of((Vi squared) -(4)(a/2)(Xi))))/2)
Does this work? where does Xf go actually and where does t go.... Can any1 help?