Riddlez ¿

[Pineapple]

ok then wait.

Hey congrats, i just noticed i made over 1272

 

[Hero]

FREE GAME!!

Anyways I found this somewhere on the internet...i think it is pretty hard..

so here it is

"At noon and midnight the hour and minute hands are exactly coincident with each other. How many other times between noon and midnight do the hour and minute hands cross?"

Anyone care to try?

 

[w/e]

Hmm...
Seems pretty easy but I think there's more to it....

13 if you count them crossing noon and midnight and 11 if you only count the times they cross in between...?

 

[Pineapple]

Is it none? Because they don't cross (X), there on top on each other.

 

[Amfidamant]

Actually, It's only ten times.


Cause the eleventh time is the first one too. Or somethign liek that, I already got confused.

 

[Tharius]

It's ten times if you don't count them "crossing" (i.e. overlaid, for Pineapple) at noon and midnight, and twelve times, if you count both noon and midnight.

The crossing times are approximately 1:06, 2:11, 3:16, 4:22, 5:27, 6:32, 7:38, 8:43, 9:48, and 10:54.

For Silverhawk's riddle, Pineapple's solution is correct, assuming that the hat-giver told the three men both the number of total hats, and the color proportions, having removing the other two hats from sight. Given this, the third man would reason as such:

If the two hats that the first man saw were both white, then he could have deduced that his hat was red, as there were only two white hats in total, but since he did not know what color his hat was, he saw at least one red hat.

The second man would have reasoned similarly, and thus could also not have seen two white hats.

Since I see one white hat, it is impossible that my hat is also white, because if it were white than the person wearing the red hat would have seen two white hats and would therefore have deduced that his hat was red. Therefore, since my hat cannot be white, it is red.

I still can't figure out how Hero thinks that Pineapple's solution is identical to his....


P.S. I know that there are already posted solutions to both of these, but I felt that both of them needed some clarification.

What?

....
Don't look at me like that.

 

[Hero]

Actually, It's only ten times.


Cause the eleventh time is the first one too. Or somethign liek that, I already got confused.

You are up next Amfidamant

anyway this is how u get the answer...

in real time there is no 12th hr on the clock....that starts a new day

so everything goes back by 1 hr

hence there is not 24 hrs in a day

ok so there is no 12 on the clock everything moves back 1 hr. 1 becomes 0 (a new day) 2 becomes 1 3 becomes 2,etc..

so what happens you ask?

you don't count 0 right?

you don't go 0,1,2,3
you just go 1,2,3,4,5,etc..
so then you do the same

instead of 1,2,3
it is no 0,1,2
because everything went back 1 hr because there is only about 23 hrs per day

so..

1-0(now this is not considered any time...because there is no 00:00 o clock..)
2-1 (1
3-2 (2
4-3 (3
5-4 (4
6-5 (5
7-6 ( 6
8-7 ( 7
9-8 ( 8
10-9 (9
11-10 (10 (The answer)
11-0 (New Day)

 

[Tharius]

Umm... what?

The reason that the hands cross less than eleven times is because the hour hand is advancing as well, albeit at a slower rate (at 1/12th the speed, in fact). If the hour hand was stationary, and positioned anywhere except pointing at the 12, the hands would "cross" exactly 12 times between noon and midnight, at 12:xx, 1:xx, 2:xx, 3:xx, up until 11:xx. This is because there are 12 hour-long intervals between noon and midnight, and each cycle of the minute hand takes exactly one hour. However, since the hour hand is rotating at 1/12th the rate of the minute hand, it takes longer than an hour (60 + (12 * 60)/11, or slightly more than 65.45 minutes) for the minute hand to "cross" the hour hand again.

This has nothing to do with the day mythically being less than twenty-four hours long.

P.S. In military time, where the time intervals are exactly the same as "normal" timekeeping, they do count from 0 (technically, 0000), up to 2359.

 

[SilverHawk]

In case anyone cares, Pineapple got mine right.

 

[Tharius]

It's been over twenty-four hours.... does that make it free game?

 

[Pineapple]

yea its free

 

[Tharius]

I suppose I'll do one along the same lines as Silverhawk's....

Three intelligent men are in a room. Another man walks in with five hats - three red and two white. After showing the men the five hats, he blindfolds each man, places a hat on each of their heads, then hides the other two hats out of sight. He then removes the blindfold from one man, and asks him what color hat he is wearing. That man looks at the other two, and says he has no idea, then leaves the room with his hat. The hat-giver then repeats the process with the second man, who looks at the one remaining man, but he also says that he does not know, and leaves the room, taking his hat with him. He then asks the third man, without removing his blindfold. The third man immediately says, "I know what color my hat is."

What color is the third man's hat, and how did he know for certain?

 

[SilverHawk]

Interesting twist on this. I like it.

The hat is red. The only way that the first man would know is if he saw two white hats. Since he didn't know, there are either two reds, two whites, or one of each. The only way for the second man to know would be for him to see a white hat. However, since he didn't know, the man's hat must've been red.

 

[Tharius]

Since he didn't know, there are either two reds, two whites, or one of each.

The only part I'd question would be the bolded part, but as far as I can tell, SilverHawk got the answer correct. Clarification for others:

The first man would have reasoned the same way as in SilverHawk's question, i.e. he would have not seen two white hats, since that would make his hat red by default. Therefore, he either saw two red hats or one red hat and one white hat.

The second man could not have seen a white hat, since he would have deduced how the first man could fail to answer correctly, and if he had seen a white hat, knowing that there was at most one white hat between the two remaining men, his hat would therefore be red.

The third man, realizing that either both his and the second man's hat were red, or that one was red and one was white and that he was not wearing the white one, could conclude that, in either instance, his hat would be red.


You're up, SilverHawk.

 

[SilverHawk]

The only part I'd question would be the bolded part

Yeah, mistake on my part. Sorry.

Hmm...I got nothing for now. Free game.

 

[SFilip]

Every morning a servant of an English lord leaves the castle and goes to the baker to bring cookies for his master. The baker always packs the cookies in a box and writes how many there are. However this morning the servant looked at the number and saw that the baker wrote it on a different way so he took a pen and added something to the original label. This way he was able to take 1/3 of the cookies without anybody knowing it. What did write and how many cookies were initially in the box?

 

[Amfidamant]

I have two guesses:

The cooker used Roman numbers to write the ammount of cookies. I didn't think of any number yet, thou.

The cooker wrote number 99 or 9 and usually placed a dot or line below the number, and one day he forgot that, so the servant simply put the dot / line above 99 / 9 , thus making it 66/ 6

So, originally, there were 99 or 9 cookies

 

[SFilip]

Good thinking, but no, it wasn't the a line/dot that he added.

 

[Amfidamant]

Hm...

Maybe then what he did was something like...

The cooker used roman numbers to write the ammount of cookies, and one day he wrote the numbers in arabic. There were 11 cookies in the box.

The servant then re-converted the arabic number to roman, making it VII, and thus leaving only 8 cookies in the box, eating three himself.

yet, It's not exactly 1/3 of teh cookies..

 

[Demi666]

the impossible riddle..

from a number 0.009-999999999999999999999999999999999910.9745887 what exact number am i thinkin off?