inputting chars to 2d array

[perkeyone]

hey guys,
i keep forgetting the syntax of cin.get and getchar etc

anyways, i am trying to design a c++ program that will prompt for the user to input something like this

0 0 0 0 r
0 1 1 1 r
1 0 0 1 r
1 1 1 2 r

and i want to store that input in a 2d array

i want to ignore the spaces
(so it wont matter if the user spaces it out or not)

 

[Samael88]

Can't you just do a simple skip thing in your program for that?

If (inputchar[current] == " ") 
{
   current++;
}

I don't know how you are taking the input now, but does that work?

 

[perkeyone]

umm are those part of the string headerfile? or are those just variables you made up?

 

[GooS]

Sorry for answering with code, but couldn't come up with a way to explain it at the moment.

Does not check for whitespaces but puts input such as:

123
321
231

into a vector as chars.

0: [[1][2][3]]
1: [[3][2][1]]
2: [[2][3][1]]

hope it helps a little!

#include <string>
#include <vector>
#include <iostream>

int main(int argv, char * args[])
{
   std::string input;
   std::vector< std::vector<char> > first_dimension;
   std::vector<char> * second_dimension;

   for(unsigned int i = 0; i < 5; ++i) // 5 second dimensions put into the first
   {
      std::cin >> input;
      second_dimension = new std::vector<char>;
      for(unsigned int j = 0; j < input.length(); ++j)  // Can currently put how many chars you want into the second dimension
      {
         second_dimension->push_back(input.at(j));
      }
      first_dimension.push_back(*second_dimension);
      delete second_dimension;
   }

   // std::cout << first_dimension[3][2]; // testline
   return 0;
}

//==GooS

 

[perkeyone]

can i get a version that doesnt use vectors?
i am going to assume that the input is only 5 columns (not including spaces)
and up to 20 rows (but not necessarily 20)

so this input would be valid

1111r

and so would this

1 1 1 1 R
2 2 2 2 L

anjd any other number of rows of 5 chars (not including spaces)