Rearranging String Characters

[ShadowInTheD]

Is there an efficient way (like using loops) to switch string characters so they're much easier to fix and all work the same so that they don't conflict with each other?

i.e. string "ABCDEF" --> "FCEBDA"

 

[TriggerHappy]

Not tested, sorry about the BJ's.

function Shift takes integer a, string s returns string
    set a = GetRandomInt(0, a)
    return ((SubStringBJ(s, a, (StringLength(s) - 1 )) + SubStringBJ(s, 1, (a - 1 ))))
endfunction

function Unshift takes integer a, string s returns string
    set a = GetRandomInt(0, a)
    return ((SubStringBJ(s, ((StringLength(s) - a) + 1), (StringLength(s) - 1)) + SubStringBJ(s, 1, (StringLength(s) - a ))))
endfunction

 

[ShadowInTheD]

This works with a 48 character string?

 

[TriggerHappy]

This works with a 48 character string?

Be my guest to test it :thup:

 

[ShadowInTheD]

What and how does it swap?

Oh wait.. So can the same characters that got swapped get red back for a save/load code?

 

[TriggerHappy]

You would use it like this, I haven't really tested this.

call Shift(StringLength(string), string)
//same for unshift

Oh wait.. So can the same characters that got swapped get red back for a save/load code?

Thats the point of the Unshift function

 

[ShadowInTheD]

So it's not actually random (they both call for a random integer)

 

[TriggerHappy]

So it's not actually random (they both call for a random integer)

So the GetRandomInt functions aren't random enough for you?

 

[ShadowInTheD]

No, it's actually that the randomness is a problem. I don't want it to be random at all, at least to where it can be decoded correctly. Because a random integer between 1 and 48 has a 1/48 chance of == a random integer between 1 and 48. Similarly if they actually consistently are the same ever time, what about 2 times? I want it to NOT be random so I can decode it.

 

[TriggerHappy]

Try this.

function Shift takes string s returns string
    return ((SubStringBJ(s, 3, (StringLength(s) - 1 )) + SubStringBJ(s, 1, (3 - 1 ))))
endfunction

function Unshift takes string s returns string
    return ((SubStringBJ(s, ((StringLength(s) - 3) + 1), (StringLength(s) - 1)) + SubStringBJ(s, 1, (StringLength(s) - 3 ))))
endfunction

Just make sure your strings length is > than 3.

You could also "save" the random number as well.

 

[ShadowInTheD]

Is there any other way I could do it? Maybe I just need more help with strings, THEY'RE SO ANNOYING.. It's stupid that the character positions aren't labeled, but rather the "gaps" between the characters.

Anyway, I'm looking more for like 15 character changes? Is there anyway to do that using a loop to do it all really fast?

 

[TriggerHappy]

Is there any other way I could do it? Maybe I just need more help with strings, THEY'RE SO ANNOYING.. It's stupid that the character positions aren't labeled, but rather the "gaps" between the characters.

Anyway, I'm looking more for like 15 character changes? Is there anyway to do that using a loop to do it all really fast?

Have you even tested my functions?

Test them, then tell me if you are satisfied.

 

[ShadowInTheD]

I know exactly what they do (or at least should do). It just seems so inefficient to make like 15 functions and call them all.. isn't there a loop that can do it all in like 5 lines, instead of like 50?

 

[TriggerHappy]

Why are you afraid of performance in a Save/Load Code?

And if you did a loop, you would just be calling X amount of function however many times the loop runs.

I'll say it once more, try the functions, and tell me if you are satisfied.

 

[ShadowInTheD]

It's not performance... I made like 10,000 mistakes doing it with just 10 lines of code, you CAN'T make "relative" mistakes using a loop. And decoding it is that much easier too.

 

[WolfieeifloW]

You want a completely random rearrangement?
Or you want it like in your first post where "Hello" would become "olleH"?

 

[ShadowInTheD]

It shouldn't be random. It's for a Save/Load code, so it needs to not be random as it needs to be decrypted.

 

[TriggerHappy]

It shouldn't be random. It's for a Save/Load code, so it needs to not be random as it needs to be decrypted.

It can be random

You can store the "random" value somewhere in the code, then re-use it.

Or you can just use a constant value.

 

[ShadowInTheD]

If I were going to randomly mix up characters, and save it with a random value, that would be kind of complex.. and regardless, doing it that way would REQUIRE a loop or like 239023850923 lines of code.

 

[TriggerHappy]

Actually, no..

// if you had a save encode function..
local string array s
set s[1] = Save(value1)
set s[2] = Save(value2)
set code = Save(GetRandomInt(1, 10)) + s[1] + s[2]

// And if you had a decode function
local integer random = Load(SubString(yourcode, 0, 1))